√70以上 (x y z)^3 expansion 303177-(x+y+z)^3 expansion

We know the corollary if a b c = 0 then a 3 b 3 c 3 = 3 a b c Using the above identity taking a = x − y , b = y − z and c = z − x , we have a b c = x − y y − z z − x = 0 then the

(x+y+z)^3 expansion- Expand the first two brackets (x −y)(x − y) = x2 −xy −xy y2 ⇒ x2 y2 − 2xy Multiply the result by the last two brackets (x2 y2 −2xy)(x − y) = x3 − x2y xy2 − y3 −2x2y1 Inform you about time table of exam 2 Inform you about new question papers 3 New video tutorials information

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