[最も選択された] f(x)=x^3 2 inverse function 269363-The inverse of function f(x) = x^3 + 2 is mcq

Find the inverse of f(x) = 3x/(x2) and check it Find the inverse of f(x) = 3x/(x2) and check itCalculate the inverse function of the given function simply by following the below given steps Let us take one function f (x) having x as the variable Consider that y is the function for f (x) Swap the variables x and y, then the resulting function will be x Now, solve the equation x Given the function f (x) f ( x) we want to find the inverse function, f −1(x) f − 1 ( x) First, replace f (x) f ( x) with y y This is done to make the rest of the process easier Replace every x x with a y y and replace every y y with an x x Solve the equation from Step 2 for y y

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The inverse of function f(x) = x^3 + 2 is mcq

25 ++ tan^2x sec^2x identity 283114-Is tan^2x-sec^2x=1 an identity

Yes, sec 2 x−1=tan 2 x is an identity sec 2 −1=tan 2 x Let us derive the equation We know the identity sin 2 (x)cos 2 (x)=1 ——(i) Dividing throughout the equation by cos 2 (x) We get sin 2 (x)/cos 2 (x) cos 2 (x)/cos 2 (x) = 1/cos 2 (x) We know that sin 2 (x)/cos 2 (x)= tan 2 (x), and cos 2 (x)/cos 2 (x) = 1 So the equation (i) after substituting becomes$$\tan 2x \neq \sec 2x \sin 2x \cos 2x $$ Based on the proof computed above, the given equation is not an identity Become a member and unlock all Study Answers Is tan^2x1=secx a pythagorean identityThe Pythagorean identity tells us that no matter what the value of θ is, sin²θcos²θ is equal to 1 We can prove this identity using the Pythagorean theorem in the unit circle with x²y²=1 Created by Sal Khan Google Classroom Facebook TwitterFree multiple angle identities list multiple angle identities by request stepbystep This

How Many Can You Derive From First Principles Ppt Download

Is tan^2x-sec^2x=1 an identity

選択した画像 expand the following (1/x y/3)^3 112412-Expand (1/x+y/3)^3 class 9

To expand this, we're going to use binomial expansion So let's look at Pascal's triangle 1 1 1 1 2 1 1 3 3 1 Looking at the row that starts with 1,3, etc, we can see that this row has the numbers 1, 3, 3, and 1 These numbers will be the coefficients of our expansion So to expand , Ex 25, 4 Expand each of the following, using suitable identities (x 2y 4z)2 (x 2y 4z)2 Using (a b c)2 = a2 b2 c2 2ab 2bc 2ac Where a = x , bExpand the following ` (i) (3a2b)^ (3) (ii) ( (1)/ (x) (y)/ (3))^ (3)` (iii) ` (4 (1)/ (3x))^ (2)` Watch later Share Copy link Info Shopping Tap to unmute If playback doesn't begin

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Expand (1/x+y/3)^3 class 9